For Loop (Read Number from Console and Check if it is a Palindrome Number)

    /*
      Read Number from Console and Check if it is a Palindrome Number
      This Java example shows how to input the number from console and
      check if the number is a palindrome number or not.
     */
    
    import java.io.BufferedReader;
    import java.io.IOException;
    import java.io.InputStreamReader;
    
    public class InputPalindromeNumberExample {
    
    public static void main(String[] args) {
    
    System.out.println("Enter the number to check..");
    int number = 0;
    
    try
    {
    //take input from console
    BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
    //parse the line into int
    number = Integer.parseInt(br.readLine());
    
    }
    catch(NumberFormatException ne)
    {
    System.out.println("Invalid input: " + ne);
    System.exit(0);
    }
    catch(IOException ioe)
    {
    System.out.println("I/O Error: " + ioe);
    System.exit(0);
    }
    
    System.out.println("Number is " + number);
    int n = number;
    int reversedNumber = 0;
    int temp=0;
    
    //reverse the number
    while(n > 0){
    temp = n % 10;
    n = n / 10;
    reversedNumber = reversedNumber * 10 + temp;
    }
    
    /*
    * if the number and it's reversed number are same, the number is a
    * palindrome number
    */
    if(number == reversedNumber)
    System.out.println(number + " is a palindrome number");
    else
    System.out.println(number + " is not a palindrome number");
    }
    
    }
    
    /*
    Output of the program would be
    Enter the number to check..
    121
    Number is 121
    121 is a palindrome number
    */